2. Given a firm’s demand function, P = 24 - 0.5Q and the average cost function, AC = Q2 – 8Q + 36 + 3/Q, calculate the level of output Q which
a) Maximizes total revenue
Since demand function is P = 24-0.5 Q
The total revenue will be TR =PQ=( 24-0.5Q) Q= 24-0.5Q2
To maximize TR , we find the derivative and set it to 0.
Hence first order condition dR/dQ =24 – 2 ( 0.5 ) Q
= 24 – Q = 0
Q = 24.
The second order derivation d2R/dQ2 to be negative .
Since dR/dQ2 = -1
Which is negative, hence total revenue is maximized when output is 24 units .
b) From profit function.
P = TR – TC
TC = AC X Q
= ( Q2 – 8 Q + 36 + 3 / Q ) X Q
= Q3 - 8 Q2 + 36 Q + 3
TR = (24 – O.5 Q ) Q
= 24Q – 0.5 Q2 after substituting TR & TC we get
P = ( 24 Q – 0.5 Q2 ) – ( Q3- 8 Q2 + 36 Q + 3 )
dP/dQ = ( 24 – Q – 3 Q2 + 16 Q – 36 )
= - 3Q2 _15 Q -12
Now set = dπ /dQ = 0
-3Q2 + 15 Q – 12 = 0
Dividing by 3 we get q2 +5 q – 4 = 0
(Q - 4 ) (Q – 1) = Q = 4 or 1
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